3x^2+7x+4=180

Solution for 3x^2+7x+4=180 equation:

3x^2+7x+4=180

We move all terms to the left:

3x^2+7x+4-(180)=0

We add all the numbers together, and all the variables

3x^2+7x-176=0

a = 3; b = 7; c = -176;
Δ = b2-4ac
Δ = 72-4·3·(-176)
Δ = 2161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{2161}}{2*3}=\frac{-7-\sqrt{2161}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{2161}}{2*3}=\frac{-7+\sqrt{2161}}{6}
$